1) The statement that determines if the null hypothesis is

rejected or not is called the

A. decision rule

B. critical value

C. test statistic

D. alternate hypothesis

2) What are the critical z-values for a two-tailed hypothesis

test if the significant level = 0.01?

A. ± 2.58

B. ± 1.65

C. ± 2.33

D. ± 1.96

3) An independent consumer testing lab preformed a statistical

test on 25 type-C alkaline batteries and calculated the mean life

for a particular use before they failed was 22.5 hours. The

distribution of the lives approximated a normal distribution. The

standard deviation of the distribution was 1.1 hours. Information

on the package states that the batteries should last 24 hours.

The test question was if this difference between the test

statistics and the stated life of the battery was significant? The

.05 significant level was selected for the test. Which is the

correct statement?

A. The difference cannot be evaluated with this small of a

sample.

B. The difference indicates that the batteries are not good.

C. The difference was not significant.

D. The difference was significant; the batteries do not meet the

stated length of time.

4) K & S Construction, located in Phoenix, Arizona, is

working on its business plan for the upcoming year. They did a

study to determine if they should focus on building condominiums or

individual houses. A building study, which had been conducted by

the state, indicated that 60 percent of those families looking to

buy a home in Arizona desired to buy a condominium. K & S

Construction wanted to know if this figure applied to Phoenix. They

collected a sample of 500 individuals that had expressed plans to

buy a new home. The z-distribution was selected for this proportion

test. The null hypothesis is p = 0.60 and the alternate is p ≠

0.60. The significant level selected was .05. From the sample of

500, it was determined that 290 wanted to buy a condominium. What

decision should be made regarding the null hypothesis?

A. Cannot accept nor reject it based on the information

given

B. The test level of .05 is not acceptable

C. Reject it

D. Fail to reject it

5) In classical hypothesis testing, the test statistic is to the

critical value what the ________________.

A. test statistic is to the p-value

B. level of significance is to the test statistic

C. critical value is to alpha

D. p-value is to alpha

6) A statistician was setting up a hypothesis test with a level

of significance dictated by upper management. However, she was

concerned that the test she wished to perform might have

unacceptable large possibilities of Type II error, ß. Which of the

following would solve this problem?

A. Convince upper management to use a smaller p-value.

B. Convince upper management to reduce the level of significance

of the test.

C. Convince upper management to use a larger sample.

D. Convince upper management to use a larger p-value.

7) Thomas Delivery has a fleet of 24 trucks that are utilized

for the companies; business. Electro-Lite, a manufacturer of spark

plugs, claims that its spark plugs have an average life in excess

of 25,000 miles. The purchasing agent at Thomas Delivery purchased

24 sets and found that the sample average life was 26,300 miles,

the sample standard deviation was 1,500 miles, and the computed

test statistic was t = 3.423. Based on these findings, at the 0.05

level, is there enough evidence to accept the manufacturer’s

claim?

A. Electro-Lite claims are not supported by the test

results.

B. Electro-Lite claims are supported; the spark plugs do exceed

the mean of 25,000 miles.

C. Electro-Lite claims cannot be supported or denied with the

test results.

D. Electro-Lite claims are just an advertising promotion.

8) A machine is set to fill the small size packages of Good and

Better candies are packaged with 60 pieces of candies in each bag.

Sampling results revealed: 3 bags of 61, 2 bags of 59, 1 bag of 58,

and 2 bags of 62. How many degrees of freedom are there?

A. 9

B. 7

C. 1

D. 8

9) If the paired differences are normal in a test of mean

differences, then the distribution used for testing is the

A. normal distribution

B. F distribution

C. Chi-Square

D. Student t distribution

10) Golf balls that are properly manufactured will have a

rebound height of 42 inches when dropped by a testing machine from

a height of 5 feet. The quality control inspector is concerned that

a new manufacturing machine is not properly calibrated and that the

resulting golf balls are falling short of the desired height. At

random, 100 golf balls were selected for a test. The test results

indicated that the rebound height was 41.6 inches with a standard

deviation of 0.5. At the .05 significant level, what is the result

of the test?

A. There is no significant difference.

B. A larger test sample is needed.

C. There is a significant difference; the golf balls are

defected.

D. A decision regarding a significant difference cannot be

made.

11) A recent study by College Stat Company reported a nationwide

survey of college students determined that students spend 2 hours

studying for each hour in the classroom. Professor Baker at State

College wants to determine whether the time students spend at her

college is significantly different from the national average of 2

hours. A random sample of 20 statistics students resulted in an

average of 1.75 hours with a standard deviation of 0.24 hours. A

t-test was conducted at the 5% level of significance. The

calculated value of t was -4.03. What was Professor Baker

decision?

A. Cannot make a decision at this time; more data is

required.

B. Reject the alternative hypothesis statement.

C. Fail to reject the null hypothesis.

D. Reject the null hypothesis, the test statistic exceeds the

critical value.

12) In a test for the equality of two variances (two-tailed),

when the populations are normal, a 5% level of significance was

used. Sample sizes were n1 = 13 and n2 = 10. The upper critical

value for the test is

A. =FINV(0.05, 12, 9).

B. =FINV(1-0.025, 13, 10).

C. =FINV(0.025, 12, 9).

D. =FINV(0.025, 13, 10).

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